Respuesta :
[tex]kx+c=9\ \ \ |-c\\\\kx=9-c\ \ \ \ |:k\neq0\\\\\boxed{x=\dfrac{9-c}{k}}[/tex]
Hello!
To solve for x you need to isolate x on one side as seen below.
kx+c=9
kx+c-c=9-c
kx=9-c
kx/k=(9-c)÷k
x=[tex] \frac{9-c}{k} [/tex]
I hope this helps!
To solve for x you need to isolate x on one side as seen below.
kx+c=9
kx+c-c=9-c
kx=9-c
kx/k=(9-c)÷k
x=[tex] \frac{9-c}{k} [/tex]
I hope this helps!