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the vertex of this parabola is at (-4 -1). when the y-value is 0, the x-value is 2. What is the coefficient of the squares term in the parabola’s equation?

the vertex of this parabola is at 4 1 when the yvalue is 0 the xvalue is 2 What is the coefficient of the squares term in the parabolas equation class=

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Luv2Teach
The standard form for this parabola is [tex]x=a(y-k)^2+h[/tex] because this is a sideways-opening parabola.  Our h and k values for the vertex are (-4, -1).  And it goes through (2,0).  We just need to solve for the a.  Filling in accordingly, [tex]2=a(0+1)^2-4[/tex] so 2 = a - 4.  a = 6.  A above.
khia46
The correct answer is A

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