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there is a 75% chance mom will order chinese takeout for dinner, a 50% chance she will take you to a movie, and a 60% chance she will order both chinese take out and take you to the movies. what is the chance she will order chinese take out or take you to the movies (probabilities of unions)

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frika
Let [tex]p_1 [/tex] be the probability that mom will order chinese takeout for dinner and [tex]q_1[/tex].

Let [tex]p_2 [/tex] be the probability that mom will take you to a movie.

Let [tex]p_3 [/tex] be the probability that mom will order both chinese take out and take you to the movies.
Using the formula (Addition Principle) for not mutually exclusive events:

[tex]P(A\cup B)=P(A)+P(B)-P(A\cap B)[/tex]
the chance that mom will order chinese take out or take you to the movies is:
[tex]P=p_1+p_2-p_3=0.75+0.5-0.6=0.65[/tex]






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