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Luv2Teach
The standard form form for a circle is [tex](x-h)^2+(y-k)^2=r^2[/tex], where h and k are the center's coordinates respectively, and r is the radius.  The first circle has a center at the origin, so the center's coordinates are (0, 0).  Counting from the center straight across or up or down to a point on the circle tells us that the radius is 5.  Our equation then is [tex](x-0)^2+(y-0)^2=5^2[/tex], or simplifying, [tex] x^{2} +y^2=25[/tex].  The second circle has a center of (5, 4).  The radius is 3.  So the equation for that circle is [tex](x-5)^2+(y-4)^2=9[/tex].  The last circle has a center of (4, 3) and a radius of 5.  The equation for that circle is [tex](x-4)^2+(y-3)^2=25[/tex].  And there you go!
yedida

Answer:

First circle has a center of (0,0) and a radius of 5  

(x – 0) ^2 + (y – 0) ^2 = 5^2 or x^2 +y^2 = 25

The second circle has a center of (5, 4).  The radius is 3.

(x – 5) ^2 + (y – 4) ^2 = 9

The last circle has a center of (4, 3) and a radius of 5.  

(x – 4) ^2 + (y – 3) ^2 = 25  

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