Respuesta :
Number of electrons that was displaced in this reaction = 2.
E⁰ = (0.0592/n)log K
log K = (E⁰*n)/0.0592 = 1.05*2/0.0592
K = 10^(1.05*2/0.0592)= 2.97 *10³⁵
E⁰ = (0.0592/n)log K
log K = (E⁰*n)/0.0592 = 1.05*2/0.0592
K = 10^(1.05*2/0.0592)= 2.97 *10³⁵