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Any one know how to find the roots of an equation?



A. 1/4 ± Square root of 10
B. 2/4 ± (i Square root of 10)/4
C. 1 ± (i Square root of 14)/2

i would like to know HOW to solve this problem.

Any one know how to find the roots of an equation A 14 Square root of 10 B 24 i Square root of 104 C 1 i Square root of 142 i would like to know HOW to solve th class=

Respuesta :

apologiabiology
so what you do is
make into ax^2+bx+c=0 form

add-9/2 to both sides
y^2-2y+9/2=0
now we use the quadratice formula which is
x=[tex] \frac{-b+/- \sqrt{b^{2}-4ac} }{2a} [/tex]

ax^2+bx+c=0
1y^2-2y+9/2
a=1
b=-2
c=9/2
subsitute
x=[tex] \frac{-(-2)+/- \sqrt{(-2)^{2}-4(1)(9/2)} }{2(1)} [/tex]
x=[tex] \frac{2+/- \sqrt{4-(36/2)} }{2} [/tex]
x=[tex] \frac{2+/- \sqrt{4-(18)} }{2} [/tex]
x=[tex] \frac{2+/- \sqrt{-14} }{2} [/tex]
x=[tex] \frac{2+/- \sqrt{-14} }{2} [/tex]
x=[tex] 1+/- \frac{\sqrt{-14} }{2} [/tex]
x=[tex] 1+/- \frac{\sqrt{14} \sqrt{-1}}{2} [/tex]
x=[tex] 1+/- \frac{\sqrt{14} i }{2} [/tex]
x=[tex] 1+/- \frac{ i \sqrt{14} }{2} [/tex]

answer is C



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