To approach the runway, a pilot of a small plane must begin at 15 desent starting from a height of 2,530 feet above the ground.
To the nearest tenth of a mile, how many miles from the runway is the airplane at the start of this approach?
A. 0.5 mi
B. 1.6 mi
C. 1.9 mi
D. 9,755.2 mi

check the picture below.

since there are 5280 feet in 1 mile, how many miles are there in 9775.169362045371 ft?

[tex]\bf \begin{array}{ccll} feet&miles\\ \text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\ 5280&1\\ 9775.169362045371&m \end{array}\implies \cfrac{5280}{9775.169362045371}=\cfrac{1}{m} \\\\\\ m=\cfrac{9775.169362045371\cdot 1}{5280}[/tex]

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brejae51 brejae51 · Answer 2 · 2022-01-10T00:16:40+01:00

brejae51 brejae51

10-01-2022

Answer:

9775.169362045371 or 9775.169362045371/5280=1.9

Step-by-step explanation:

:0

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To approach the runway, a pilot of a small plane must begin at 15 desent starting from a height of 2,530 feet above the ground. To the nearest tenth of a mile, how many miles from the runway is the airplane at the start of this approach? A. 0.5 mi B. 1.6 mi C. 1.9 mi D. 9,755.2 mi

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To approach the runway, a pilot of a small plane must begin at 15 desent starting from a height of 2,530 feet above the ground.
To the nearest tenth of a mile, how many miles from the runway is the airplane at the start of this approach?
A. 0.5 mi
B. 1.6 mi
C. 1.9 mi
D. 9,755.2 mi