Donaluna
Donaluna
01-06-2018
Mathematics
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How to do the problem
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clairebear11213
clairebear11213
01-06-2018
There are 153 people who each ate 1/4 pounds. Therefore, the amount of watermelon eaten is 153/4 pounds.
The amount of watermelon served is
[tex]8 \frac{1}{4} + 9 \frac{1}{4} + 8 \frac{7}{8} + 9 \frac{5}{8} + 10 \frac{3}{4}[/tex]
[tex]= \frac{8 \times 4 + 1}{4} + \frac{9 \times 4 + 1}{4} \\ + \frac{8 \times 8 + 7}{8} + \frac{9 \times 8 + 5}{8} \\ + \frac{10 \times 4 + 3}{4} [/tex]
[tex] = \frac{33}{4} + \frac{37}{4} + \frac{71}{8} + \frac{77}{8} + \frac{43}{4} \\ = \frac{33 \times 2}{4 \times 2} + \frac{37 \times 2}{4 \times 2} + \frac{71}{8} \\ + \frac{77}{8} + \frac{43 \times 2}{4 \times 2} [/tex]
[tex] = \frac{66 + 74 + 71 + 77 + 86}{8} [/tex]
[tex] = \frac{374}{8} = \frac{186}{4} [/tex]
There is 186/4 total watermelon. Minus the 153/4 that was eaten,
[tex] \frac{186 - 153}{4} = \frac{33}{4} = 8 \frac{1}{4} [/tex]
The leftover watermelon is 8 & 1/4 pounds.
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