Answer:
Step-by-step explanation:
Given is a triangle EGH with sides 49, 58.8 cm and third side as two parts with 35 and x+1 cm.
We have to find x.
Consider triangle GED and EDH separately. We use sine formula to find GD and HD
Use sine formula for triangles
[tex]\frac{35}{sinGED} =\frac{49}{sinGDE} \\\frac{x+1}{sinDEH}=\frac{58.8}{sinEDH} \\[/tex]
But sin GED = sin DEH (angle bisector)
Sin GDE = sin EDH (supplementary angles have the same sine)
So 35/49 = (x+1)/58.8
5/9=x+1/58.8
294 =9x+9
285 =9x
x =285/9 = 95/3
= 31.33 cm.