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[tex](p^2+p-6)-(p^2-4p)=p^2+p-6-p^2+4p=5p-6\\\\(5p-6)-(p-9)=5p-6-p+9=4p+3[/tex]

Answer:

First question :

Here, the given problem,

[tex]p^2+p-6-(p^2-4p)[/tex]

[tex]=p^2+p-6-p^2+4p[/tex]

[tex]=p^2(1-1)+p(1+4)-6[/tex]

[tex]=5p-6[/tex]

Thus, the result is 5p -6.

Second question:

Let to get p-9 we need to subtract X from 5p-6,

I.e.

[tex]5p-6-X = p - 9[/tex]

[tex]5p-6-p+9=X[/tex]

[tex]\implies X = 4p + 3[/tex]

Thus, the result would be 4p + 3.

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