Using the Equation:
v² = vi² + 2 · a · s → Eq.1
where,
v = final velocity
vi = initial velocity
a = acceleration
s = distance
We know that vi = 0 because the ball was at rest initially.
Therefore,
Solving Eq.1 for acceleration,
v² = vi² + 2 · a · s
v² = 0 + 2 · a · s
v² = 2 · a · s
Rearranging for a,
a = v ²/2·s
Substituting the values,
a = 46²/2×1
a = 1058 m/s²
Now applying Newton's 2nd law of motion,
F = ma
= 0.145×1058
F = 153.4 N
