Determine which of the following statements is true concerning the values described in column #1 and column #2. Column #1 Column #2 The x-coordinate of the vertex of the graph of y = −2x2 − 4x + 12 The x-coordinate of the vertex of the graph of y = x2 − 4x + 3

Hi,

1)
[tex]y=-2x^2-4x+12=-2(x^2+2x+1)+2+12=-2(x+1)^2+14\\\\ Vertex=(-1,14) \ x-coordinate=-1\\ [/tex]

2)
[tex]y=x^2-4x+3=x^2-4x+4-1=(x-2)^2-1\\\\ Vertex=(2,-1) \ x-coordinate=2\\ [/tex]

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Аноним Аноним · Answer 2 · 2019-04-15T10:43:10+02:00

Answer with explanation:

→→The equation of curve 1 ,which is in the shape of parabola is ,when represented in general form

[tex]y= -2x^2-4 x + 12\\\\ y=-2[x^2+2 x-6]\\\\ \frac{y}{-2}=(x+1)^2-6-1\\\\ \frac{-y}{2}+7=(x+1)^2[/tex]

So, Coordinate of vertex can be obtained by

→ x+1=0

x= -1

and, [tex]\frac{-y}{2}+7=0\\\\ y=14[/tex]

is equal to , (-1,14).

x-Coordinate of vertex of the function ,[tex]y=-2x^2-4 x + 12[/tex] is equal to -1.

→→→The equation of curve 2 ,which is in the shape of parabola is ,when represented in general form

[tex]y= x^2-4 x + 3\\\\ y=(x-2)^2+3-4\\\\ y=(x-2)^2-1\\\\ y+1=(x-2)^2[/tex]

So, Coordinate of vertex can be obtained by

→ x-2=0

x= 2

and, →y+1=0

y= -1

is equal to , (2,-1).

x-Coordinate of vertex of the function ,[tex]y=x^2-4 x + 3[/tex] is equal to 2.