Ten grams of a gas occupies 12.5 liters at a pressure of 42.0 cm Hg. What is the volume when the pressure has increased to 75.0 cm Hg?

Respuesta :

Based on the question, it is evident that the question is based on Boyle's Law which we will use to find the answer necessary.

Now, Boyle's Equation: P₁V₁ = P₂V₂

     V₂ = P₁V₁  ÷  P₂

∴   V₂  =  (12.5L × 42.0 cm · Hg) ÷ 75 cm · Hg

⇒  V₂  = 7 L
 
Thus, the volume when the pressure has increased to 75.0 cm Hg is 7 Litres.