Respuesta :
1 mole of any gas under standard conditions has volume 22.4 L.
So,
11.2 L * 1 mol/22.4 L= 0.5 mol
So,
11.2 L * 1 mol/22.4 L= 0.5 mol
Answer:
There are 0.5 moles in 11.2 liters of methane at standard conditions.
Step-by-step explanation:
Standard state conditions are defined by Standard Temperature & Pressure (STP) with a temperature of 0 °C or 273.15 Kelvin (K) and a pressure of 1 atmosphere (1 atm = 101 325 Pa), temperature.
At STP 1 mol of ideal gas occupies 22.4 L.
We know the volume of methane V = 11.2 liters and 1 mol of ideal gas occupies 22.4 L.
To find the moles of the gas we can apply the following formula:
[tex]Moles \:of \:gas = \:volume \:of \:gas \cdot \frac{1 \mol}{22.4 L}[/tex]
[tex]Moles \:of \:methane \:gas = 11.2 \:L \cdot \frac{1 \:mol}{22.4 \:L }=0.5 \:mol[/tex]
There are 0.5 moles in 11.2 liters of methane at standard conditions.
