Respuesta :
On reacting zinc chloride with silver nitrate, solution turns milky white.
Reason:
Following reaction occurs in present system:
ZnCl2 (aq) + 2AgNO3 (aq) → Zn(NO3)2 + 2AgCl↓
(white ppt.)
The solubility of AgCl in water is extremely poor. Infact, it is a sparingly soluble salt. Hence, it will get precipitate out. Colour of AgCl is white, hence the solution appears to be milky white.
Reason:
Following reaction occurs in present system:
ZnCl2 (aq) + 2AgNO3 (aq) → Zn(NO3)2 + 2AgCl↓
(white ppt.)
The solubility of AgCl in water is extremely poor. Infact, it is a sparingly soluble salt. Hence, it will get precipitate out. Colour of AgCl is white, hence the solution appears to be milky white.
Answer: A white precipitate of silver chloride is formed in the above reaction.
Explanation:
Double displacement reaction is defined as the chemical reaction in which exchange of ions takes place.
[tex]AB+CD\rightarrow CB+AD[/tex]
When an aqueous solution of zinc chloride reacts with an aqueous solution of silver nitrate, it leads to the formation of aqueous solution of zinc nitrate and a solid silver chloride.
The chemical equation for the reaction of zinc chloride and silver nitrate follows:
[tex]ZnCl_2(aq.)+2AgNO_3(aq.)\rightarrow Zn(NO_3)_2(aq.)+2AgCl(s)[/tex]
A white precipitate of silver chloride is formed in the above reaction.