Solutions
[tex] a^{2} [/tex] + [tex]b^{2} [/tex] = [tex] c^{2} [/tex]
10 is [tex] a^{2} [/tex] and 14 is [tex]b^{2} [/tex]
To find [tex] c^{2} [/tex] you have to add [tex] a^{2} [/tex] + [tex]b^{2} [/tex].
Calculations
[tex] 10^{2} [/tex] + [tex]14^{2} [/tex] = [tex] c^{2} [/tex]
[tex] 10^{2} [/tex] = 10 x 10
[tex] 10^{2} [/tex] = 100
[tex]14^{2} [/tex] = 14 x 14
[tex]14^{2} [/tex] = 196
Since [tex] a^{2} [/tex] + [tex]b^{2} [/tex] = [tex] c^{2} [/tex] you have to add [tex] 10^{2} [/tex] and [tex]14^{2} [/tex] .
100 + 196 = 296
To find the hypotenuse you have to square root 296.
[tex] \sqrt{269} [/tex]
= 17.2
17.2 is the hypotenuse or [tex] c^{2} [/tex]
