Respuesta :

skyvrana
Answer is C. because you flip the fraction upside down to find its reciprocal
((:
gmany
[tex]\text{The reciprocal of}\ a\ \text{is equal}\ \dfrac{1}{a}\\\\a^{-1}=\dfrac{1}{a}[/tex]
[tex]\dfrac{10b}{2b+8}\to\left(\dfrac{10b}{2b+8}\right)^{-1}=\dfrac{2b+8}{10b}[/tex]
[tex]\boxed{Answer:\ C.\ \dfrac{2b+8}{10b}}[/tex]