contestada

∆ADB ≅ ∆CDB by the _____

A. AAS Theorem.


B. SSS Postulate.


C. ASA Postulate.


D. SAS Postulate.

ADB CDB by the A AAS Theorem B SSS Postulate C ASA Postulate D SAS Postulate class=

Respuesta :

sqdancefan
The marked angles and side BD make up two adjacent angles and a side not between them. The applicable theorem is ...
   AAS Theorem

Answer:

Option A is correct

AAS theorem.

Step-by-step explanation:

AAS(Angle -Angle-Side) theorem states that:

if two angles and any side of one triangle are congruent to two angles and any side of another triangle, then these triangles are congruent

In a given triangle ADB and CDB.

[tex]\angle BAD = \angle BCD[/tex]  [Angle]                      [Given]

[tex]\angle BDA = \angle BDC=90^{\circ}[/tex]  [Angle]        [Given]

[tex]BD = BD[/tex]   {Common side}       [Side]

then by AAS theorem;

[tex]\triangle ADB \cong \triangle CDB[/tex]

Therefore, ∆ADB ≅ ∆CDB by the AAS theorem.

Otras preguntas