Respuesta :
Consider one pyramid
Side length of base = 1.5cm and its height is 1 cm
Slant height of one of the lateral faces = sqrt(1^2 + 0.75^2) = 1.25 cm
Area of one of the triangular faces = 0.5 * 1.5* 1.25 = 0.9375 cm^2
There are 8 of these so the required surface area = 8 * 0.9375
= 7.5 cm^2 Answer
Side length of base = 1.5cm and its height is 1 cm
Slant height of one of the lateral faces = sqrt(1^2 + 0.75^2) = 1.25 cm
Area of one of the triangular faces = 0.5 * 1.5* 1.25 = 0.9375 cm^2
There are 8 of these so the required surface area = 8 * 0.9375
= 7.5 cm^2 Answer
Answer:
The surface area of the 8-sided figure is 7.5 cm²
Step-by-step explanation:
The perimeter of the base of each square pyramid is 6 centimeters.
So, each side length of the base [tex]=\frac{6}{4}= 1.5\ cm.[/tex]
Two pyramids are attached by their bases and the distance between the tallest points of the two pyramids is 2 centimeters.
So, the height of each pyramid = 1 centimeter.
Now, lateral surface area of each pyramid
[tex]=2a\sqrt{\frac{a^2}{4}+h^2}[/tex]
[tex]=2(1.5)\sqrt{\frac{(1.5)^2}{4}+(1)^2}\\ \\ =3\sqrt{\frac{2.25}{4}+1}\\ \\ =3\sqrt{1.5625}\\ \\ =3(1.25)=3.75\ cm^2[/tex]
So, the total lateral surface area of two pyramids [tex]=2(3.75)=7.5\ cm^2[/tex]
Hence, the surface area of the 8-sided figure is 7.5 cm²
