Respuesta :

sqdancefan
The rational expression
[tex]\dfrac{v^{2}+1}{v^{2}-v-6}=\dfrac{v^{2}+1}{(v-3)(v+2)}[/tex]
will be undefined where the denominator is zero. Values of v that make the denominator zero are v=3 and v=-2.

Excluded values of v are -2 and 3.

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