Let's solve this problem using trigonometry. So, the relations are as follows:
[tex]sin(P)= \frac{O}{H}= \frac{5}{14}[/tex]
[tex]cos(P)= \frac{A}{H}= \frac{9}{14}[/tex]
[tex]tan(P)= \frac{O}{A}= \frac{5}{9}[/tex]
So the conclusion and answer for this problem is the third Item
