write the expression (4x-2)×6(2x+7) in the standard form of a quadratic expression ax^{2}+bx+c. What are the values of the coefficients of each term and the constant term.
find the answer for a, b, and c

Respuesta :

The coefficients a, b & c come out to be 48,144, and -84 respectively.

The given expression is:

[tex](4x-2)*6(2x+7)[/tex]

We can rewrite it as

[tex]6(4x-2)*(2x+7)[/tex]

taking 2 as common from [tex]4x-2[/tex]

[tex]12(2x-1)*(2x+7)[/tex]

Multiply [tex](2x-1)[/tex] with [tex](2x+7)[/tex]

[tex]12(4x^{2} +14x-2x-7)[/tex]

[tex]12(4x^{2} +12x-7)[/tex]

[tex]48x^{2} +144x-84[/tex]

What is the general form of a quadratic expression?

The general form of a quadratic expression is [tex]ax^{2} +bx+c=0[/tex] with [tex]a\neq 0[/tex].

If we compare [tex]48x^{2} +144x-84[/tex] with the general form of a quadratic equation

[tex]a=48\\b=144\\c=-84[/tex]

Hence, the coefficients a, b & c come out to be 48,144, and -84 respectively.

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