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27-05-2018
Mathematics

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f(x) = x^2 - 16 and g(x) = x+4. Find f/g and its domain

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27-05-2018

[tex]f(x)=x^2-16\\\\g(x)=x+4\\\\\dfrac{f}{g}(x)=\dfrac{x^2-16}{x+4}\\\\The\ domain:\ x+4\neq0\to x\neq-4\\\\\dfrac{f}{g}(x)=\dfrac{(x-4)(x+4)}{x+4}=x-4[/tex]

[tex]Used:\ a^2-b^2=(a-b)(a+b)[/tex]

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