From the description we can infer that we have the expression: [tex]41^{- \frac{2}{5} }[/tex].
Now, to write our expression as a as a root, we are going to apply the law of exponents: [tex]x^{-n}= \frac{1}{x^n} [/tex] first
[tex]41^{- \frac{2}{5} }= \frac{1}{41^{ \frac{2}{5} }} [/tex]
Next, we are going to apply the law about fractional exponents: [tex]x^{ \frac{m}{n}}= \sqrt[n]{x^m} [/tex]
[tex]\frac{1}{41^{ \frac{2}{5} }}= \frac{1}{ \sqrt[5]{41^2} } [/tex]
We can conclude that the value of B is 2.
