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A 200-kg object has a 50-Newton rightward net force being applied to it. What is the magnitude of the rightward acceleration on the object m/s^2?

Respuesta :

The formula for acceleration is force divided by mass.

Force = 50 N

Mass = 200 kg

Acceleration = ???

[tex] \frac{50}{200} = \frac{1}{4} [/tex]

[tex] \frac{1}{4} = 0.25[/tex]

~~

Acceleration = 0.25 m/s²

~~

Next time use, f = ma in a triangle,

F

M A

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I hope that helps you out!!

Any more questions, please feel free to ask me and I will gladly help you out!!

~Zoey
onyebuchinnaji

The magnitude of the rightward acceleration on the object is 0.25 m/s².

Acceleration of the object

The right ward acceleration of the object is calculated by applying Newton's second law of motion as shown below;

F = ma

where;

  • m is the mass
  • a is the acceleration of the object

Substitute the given parameters and solve for acceleration,

a = F/m

a = 50/200

a = 0.25 m/s²

Thus, the magnitude of the rightward acceleration on the object is 0.25 m/s².

Learn more about acceleration here: https://brainly.com/question/14344386

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