The manager of a quick service convenience store wants to estimate the difference in the
proportion of customers who would purchase a specialty drink if a pop-up advertisement
appeared on the self-service kiosk screen before the customer completed the order. To
investigate, the kiosk was programmed to flip a virtual coin for each customer. If the virtual
coin toss came up heads, the kiosk would display an advertisement for a specialty drink. If
the virtual coin toss came up tails, no advertisement was displayed. For each customer, the
kiosk recorded whether or not an advertisement was displayed and whether or not a
specialty drink was ordered.
The manger found that customers who received an advertisement purchased a specialty
drink.
customers did not receive an advertisement purchased a specialty drink.
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Construct a 99% confidence interval for the difference in the true proportion of customers.
Type a response