Calculate the cell potential for the following reaction as written at 25.00 degree C, given that [Zn²⁺] = 0.761 M and [Ni²⁺] = 0.0110 M.

Zn(s) + Ni²⁺ (aq) ⇄ Zn²⁺(aq) + Ni(s)

E =