f(x) = (2√√x+1)(x-1) /x + 3
a. does not exist
b. x²³/2+6x¹/2 + 4x - 3x-¹/2 /x + 3
c. x³/2+10x¹/2+4-3x ¹/2 /(x+3) ²
d. 3x³/2+10x¹/2-3x - ¹1/2/ (x+3) ²