A proton moves 0.10 m along the direction of the electric field of strength 3.0 N/C. The Electric potential difference between the protons initial and ending point is?
A. 4.8E-19 V
B. 0.30V
C. 0.33V
D. 30.0V
So I’m confused on which equation to use to solve this, I thought I could use this formula
Vi-Vf = Ed
Vi-Vf = 3 x .10 = 0.30V
But I also saw a different way to solve this doing
Q x E x d
= 1.6E-19 x 3 x .10 = 4.8E-20