a one-way analysis of variance experiment produced the following anova table. assume normality in the underlying populations. (you may find it useful to reference the q table). summary groups count average column 1 6 0.89 column 2 6 1.31 column 3 6 2.35 source of variation ss df ms f p-value between groups 8.65 2 4.33 16.65 0.0002 within groups 3.83 15 0.26 total 12.48 17 picture click here for the excel data file a. conduct an anova test at the 1% significance level to determine if some population means differ. multiple choice reject h0; we can conclude that some population means differ. reject h0; we cannot conclude that some population means differ. do not reject h0; we can conclude that some population means differ. do not reject h0; we cannot conclude that some population means differ. b. calculate 99% confidence interval estimates of μ1 − μ2, μ1 − μ3, and μ2 − μ3 with tukey’s hsd approach. (if the exact value for nt − c is not found in the table, then round down. negative values should be indicated by a minus sign. round your answers to 2 decimal places.) c. given your response to part b, which means significantly differ?