I could really use some help with these warm ups.

Let’s assume the velocity of the fast car (1) was solved for and it was 40.0 cm/s. And the velocity of the slow car (2) was solved for and was found to be 20.0 cm/s. Let’s say the initial positions given to our group are 0.0 cm for the fast car and 360 cm for the slow car. The slow car will be facing the negative direction, so its velocity will become - 20.0 cm/s. This is all done over 12 seconds.

In terms of the two mathematical equations for these lines of y1=m1x+b1, and y2=m2x+b2, what is m1? What is m2?

In terms of the equations shown, what is b1? What is b2? Remember, b is the y-intercept, which is what the y-value would be at when x = 0.

Create the two lines on the same graph needed for this scenario, including correct units for the graph. So for instance, if you know that the rate of the first car is 40 cm/s, and the car travels for 3 seconds, then in the first three seconds the car’s position changes by v(t) = x, or 40.0 cm/s.(3 sec) = 120 cm.