a vertical curve of 1000 ft is designed to connect a grade of 4% to a grade of -5%. the v.p.i. is located at station 1,500 55 and has a known elevation of 500 ft. find 1) the station of the v.p.c. (vertical point of curve and the v.p.t (vertical point of tangent) 2) the elevation of the v.p.c. (vertical point of curve and the v.p.t (vertical point of tangent) 3) the first full station number and elevation of the v.p.v 4) the location and elevation of the high point on the curve